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\( 9+8 \) som \( \frac{1}{2} \times 8-2+(3+1) \div 2+7 \times 3-9 \div 3 \)

Ask by Fitzgerald Klein. in South Africa
Jan 21,2025

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39

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The Deep Dive

Let's break it down! First, we simplify the expression step by step. Starting with \( 9 + 8 \), we get \( 17 \). Now simplifying \( \frac{1}{2} \times 8 \) gives us \( 4 \), and then subtracting \( 2 \): \[ 4 - 2 = 2. \] Next, \( (3 + 1) \div 2 \): \[ 4 \div 2 = 2. \] Now, simplifying \( 7 \times 3 \): \[ 21. \] Finally, \( 9 \div 3 = 3. \) Putting it all together: \[ 17 + 2 + 2 + 21 - 3. \] Calculating this, we have: \[ 17 + 2 = 19, \] \[ 19 + 2 = 21, \] \[ 21 + 21 = 42, \] \[ 42 - 3 = 39. \] So, the final answer is \( 39 \).

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