Question
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  1. Calculate the following:
    a. If a rabbit goes from to while accelerating at a rate of , how long did it take the rabbit to increase its speed?
    b. A cheetah accelerated by over the course of 10 seconds. If the cheetah started with a velocity of , what was the cheetah’s final velocity?
    c. A car is pushed off a 20 m cliff, how long would it take to hit the ground?
    d. A race car accelerates at for 2 seconds. If it started at , what is its final velocity?
    e. If a car drives 30 m North, and then turns around and drives 5 m South, what is the car’s total displacement? What is the car’s total distance traveled?

Ask by Martin Edwards. in the United States
Jan 23,2025

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Answer

a. The rabbit took 2.5 seconds to increase its speed from to .
b. The cheetah’s final velocity was 300 m/s.
c. It would take approximately 2.02 seconds for the car to hit the ground.
d. The race car’s final velocity is 34 m/s.
e.
  • Total Displacement: North
  • Total Distance Traveled:

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Mind Expander

To figure out how long it took the rabbit to increase its speed from to , you can use the formula , where and . Thus, the time taken is .
For the cheetah’s final velocity, use the equation . Here , , and . So, .
For the car falling from a 20 m cliff, you can use the formula for free fall: . Here and . Rearranging gives .
With the race car, you can again apply the final velocity formula where , , and . Thus, .
For the car’s total displacement, you start with 30 m North, then go 5 m South: North. The total distance traveled is simply .

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