Question
- Calculate the following:
a. If a rabbit goes from
to
while accelerating at a rate of
, how long did it take the rabbit to increase its speed?
b. A cheetah accelerated by
over the course of 10 seconds. If the cheetah started with a velocity of
, what was the cheetah’s final velocity?
c. A car is pushed off a 20 m cliff, how long would it take to hit the ground?
d. A race car accelerates at
for 2 seconds. If it started at
, what is its final velocity?
e. If a car drives 30 m North, and then turns around and drives 5 m South, what is the car’s total displacement? What is the car’s total distance traveled?
a. If a rabbit goes from
b. A cheetah accelerated by
c. A car is pushed off a 20 m cliff, how long would it take to hit the ground?
d. A race car accelerates at
e. If a car drives 30 m North, and then turns around and drives 5 m South, what is the car’s total displacement? What is the car’s total distance traveled?
Ask by Martin Edwards. in the United States
Jan 23,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
a. The rabbit took 2.5 seconds to increase its speed from
to
.
b. The cheetah’s final velocity was 300 m/s.
c. It would take approximately 2.02 seconds for the car to hit the ground.
d. The race car’s final velocity is 34 m/s.
e.
- Total Displacement:
North - Total Distance Traveled:
Solution

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To figure out how long it took the rabbit to increase its speed from
to
, you can use the formula
, where
and
. Thus, the time taken is
.
For the cheetah’s final velocity, use the equation
. Here
,
, and
. So,
.
For the car falling from a 20 m cliff, you can use the formula for free fall:
. Here
and
. Rearranging gives
.
With the race car, you can again apply the final velocity formula
where
,
, and
. Thus,
.
For the car’s total displacement, you start with 30 m North, then go 5 m South:
North. The total distance traveled is simply
.