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Select the simplification that accurately explains the following statement. \( \sqrt[8]{7}=7^{\frac{1}{3}} \) A. \( \left(7^{\frac{1}{3}}\right)^{8}=7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}}=7 \cdot\left(\frac{1}{3}+\frac{1}{8}+\frac{1}{3}\right)=7 \cdot \frac{3}{3}=7 \cdot 1=7 \) B. \( \left(7^{\frac{1}{3}}\right)^{3}=7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}}=7 \cdot 7^{\frac{1}{3}}=3 \cdot \frac{1}{3} \cdot 7=1 \cdot 7=7 \) C. \( \left(7^{\frac{1}{3}}\right)^{8}=7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}}=7^{\frac{1}{3} \cdot \frac{1}{3}} \frac{1}{3}=7^{\frac{3}{3}}=7^{1}=7 \) D. \( \left(7^{\frac{1}{3}}\right)^{8}=7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}} \cdot 7^{\frac{1}{3}}=7^{\frac{1}{3}}+\frac{1}{3}+\frac{1}{3}=7^{\frac{3}{3}}=7^{1}=7 \)

Ask by Hart Cervantes. in the United States
Jan 24,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

None of the options correctly explain the statement \( \sqrt[8]{7}=7^{\frac{1}{3}} \).

Solution

To determine which simplification accurately explains the statement \( \sqrt[8]{7}=7^{\frac{1}{3}} \), we need to analyze the options provided. First, let's rewrite the left side of the equation: \[ \sqrt[8]{7} = 7^{\frac{1}{8}} \] Now, we need to compare this with the right side, which is \( 7^{\frac{1}{3}} \). Therefore, we are actually comparing \( 7^{\frac{1}{8}} \) with \( 7^{\frac{1}{3}} \). Next, we can analyze each option to see if they correctly represent the relationship between these two expressions. ### Option A: \[ \left(7^{\frac{1}{3}}\right)^{8} = 7^{\frac{8}{3}} \quad \text{(This is incorrect)} \] The simplification does not lead to \( 7 \). ### Option B: \[ \left(7^{\frac{1}{3}}\right)^{3} = 7^{1} = 7 \quad \text{(This is also incorrect)} \] This does not relate to \( 7^{\frac{1}{8}} \). ### Option C: \[ \left(7^{\frac{1}{3}}\right)^{8} = 7^{\frac{8}{3}} \quad \text{(This is incorrect)} \] Again, this does not lead to \( 7 \). ### Option D: \[ \left(7^{\frac{1}{3}}\right)^{8} = 7^{\frac{8}{3}} \quad \text{(This is incorrect)} \] This does not lead to \( 7 \). ### Conclusion: None of the options A, B, C, or D correctly explain the statement \( \sqrt[8]{7}=7^{\frac{1}{3}} \). In fact, \( 7^{\frac{1}{8}} \neq 7^{\frac{1}{3}} \). The correct relationship is that \( 7^{\frac{1}{8}} \) is less than \( 7^{\frac{1}{3}} \). Thus, the statement \( \sqrt[8]{7}=7^{\frac{1}{3}} \) is false, and none of the provided options accurately explain it.

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Bonus Knowledge

Did you know that the roots and exponents we use today have roots (pun intended!) deeply embedded in history? The concept of roots can be traced back to ancient civilizations. The Babylonians had methods for approximating square roots, and by the time of the Greeks, mathematicians like Euclid were rigorously defining concepts of ratios that related to roots, laying groundwork for our current understanding. Talk about a journey through time! When dealing with exponents, a common mistake is forgetting the power of a power rule, which states that when you raise a power to another power, you multiply the exponents. For instance, if you see \( \left(7^{\frac{1}{3}}\right)^8 \), don't forget to multiply \(\frac{1}{3}\) by \(8\), which gives you \(7^{\frac{8}{3}}\), not some addition mishap or an unfavorable mix-up with fractions! Keep it straightforward, and the math will be your ally!

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