Question
Higher Order Thinking Lemmy walked \( \frac{7}{2} \) miles on Saturday and \( \frac{19}{4} \) miles on Sunday. Peyton walked \( \frac{43}{8} \) miles on Saturday. Who walked farther? How much farther?
Ask by Erickson Edwards. in the United States
Jan 22,2025
Real Tutor Solution
Tutor-Verified Answer
Answer
Lemmy walked farther than Peyton by \( 2 \frac{7}{8} \) miles.
Solution
To determine who walked farther and by how much, let's calculate the total miles each person walked.
### Lemmy's Total Walking Distance:
Lemmy walked on two days:
- **Saturday:** \( \frac{7}{2} \) miles
- **Sunday:** \( \frac{19}{4} \) miles
**Total Distance:**
\[
\frac{7}{2} + \frac{19}{4} = \frac{14}{4} + \frac{19}{4} = \frac{33}{4} = 8.25 \text{ miles}
\]
### Peyton's Total Walking Distance:
Peyton walked only on Saturday:
- **Saturday:** \( \frac{43}{8} \) miles
**Total Distance:**
\[
\frac{43}{8} = 5.375 \text{ miles}
\]
### Comparing Distances:
- **Lemmy:** 8.25 miles
- **Peyton:** 5.375 miles
**Difference:**
\[
8.25 - 5.375 = 2.875 \text{ miles}
\]
\[
2.875 \text{ miles} = 2 \frac{7}{8} \text{ miles}
\]
### **Conclusion:**
**Lemmy walked farther than Peyton by \( 2 \frac{7}{8} \) miles.**
Reviewed and approved by the UpStudy tutoring team
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Simplify this solution Extra Insights
To find out who walked farther, we need to compare the distances. Lemmy walked \( \frac{7}{2} \) miles on Saturday and \( \frac{19}{4} \) miles on Sunday. First, convert \( \frac{7}{2} \) into eighths for easier comparison: \[ \frac{7}{2} = \frac{28}{8} \] Now add Lemmy's Saturday and Sunday distances: \[ \frac{28}{8} + \frac{19}{4} = \frac{28}{8} + \frac{38}{8} = \frac{66}{8} \] Peyton walked \( \frac{43}{8} \) miles on Saturday. We can compare: Lemmy: \( \frac{66}{8} \) Peyton: \( \frac{43}{8} \) Now subtract to find out how much farther Lemmy walked: \[ \frac{66}{8} - \frac{43}{8} = \frac{23}{8} \] So, Lemmy walked \( \frac{23}{8} \) miles farther than Peyton.
