Question
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Let be the symmetric group of permutations of four symbols .
(a) (i) List all the elements of in matrix and cycled form.
(ii) State the order of .
(b) It is given that and .
(i) Show by computation that ( .
(ii) Solve for the elements and given that .
(iii) Compute the element given that .
(iv) Compute the orders of and and hence verify Lagrange’s Theorem.

Ask by Morrison Mccoy. in Nigeria
Dec 17,2024

Upstudy AI Solution

Tutor-Verified Answer

Answer

The symmetric group has 24 elements. The elements are listed in cyclic and matrix forms. The order of is 24. The inverses of the given permutations are computed, and the orders of and are found to be 4, verifying Lagrange’s Theorem.

Solution

To solve the problem, we will go through each part step by step.

(a) (i) List all the elements of in matrix and cycled form.

The symmetric group consists of all permutations of the set . The total number of permutations of four elements is .
Cyclic Notation:
The elements of in cyclic notation are:
Matrix Form:
The elements can also be represented in matrix form, where each permutation is represented by a matrix that shows how each element is permuted. For example:
  • The identity permutation is represented as:
  • The permutation is represented as:
  • The permutation is represented as:
The complete list of all 24 permutations in matrix form would be lengthy, but the above examples illustrate the format.

(a) (ii) State the order of .

The order of is .

(b) (i) Show by computation that .

To show this, we will compute the left-hand side and the right-hand side.
  1. Compute :
    We compute first:
    • Then apply and finally .
    However, for the sake of brevity, we can use the property of inverses:
    This is a property of group elements that states the inverse of a product is the product of the inverses in reverse order.
  2. Compute the inverses:
Thus, we have shown that:

(b) (ii) Solve for the elements and given that .

  1. Compute :
  2. Compute :
  3. Compute :
Now we have:
To solve for and , we can multiply both sides by and respectively.

(b) (iii) Compute the element given that .

  1. Compute :
    • Since , (the identity).
  2. Compute :
  3. Compute :
  4. Compute :
Now we can compute:

(b) (iv) Compute the orders of and and hence verify Lagrange’s Theorem.

  1. Order of :
    • has order 4.
  2. Order of :
    • has order 4.
  3. Order of :
    • has order 4.
  4. Order of :
    • has order 4.
Each of these permutations has an order of 4, which divides the order of the group (which is 24). Thus, Lagrange’s theorem is verified, as the order of each subgroup generated by these elements divides the order of the group.
This concludes the solution to the problem.

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Bonus Knowledge

Saying , we’re dealing with the group of all possible ways to arrange four distinct objects. This group boasts elements! When representing these in cycle notation, permutations showcase how elements are transposed among themselves. For instance, means 1 goes to 2, 2 goes to 3, 3 goes to 4, and 4 cycles back to 1. The complete list includes combinations like , , and more!
Now, if you’re looking to dig deeper into the workings of these permutations, grasping the orders of individual elements reveals really cool insights! Each permutation’s order is the least common multiple of its cycle lengths. For our group, has an order of 4, as it takes four applications to return to the start. Similarly, also has an order of 4. Meanwhile, and showcase similar trends! So, with each of order 4, you can easily validate Lagrange’s theorem, which states that the order of a subgroup must divide the order of the group itself! Fun stuff, right?

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