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Let \( G=S_{4} \) be the symmetric group of permutations of four symbols \( 1,2,3,4 \). (a) (i) List all the elements of \( G \) in matrix and cycled form. (ii) State the order of \( G \). (b) It is given that \( p=(1234), q=(3142), r=(2431) \) and \( s=(4123) \). (i) Show by computation that ( \( p q r s)^{-1}=s^{-1} q^{-1} r^{-1} p^{-1} \). (ii) Solve for the elements \( x \) and \( y \) given that \( p^{2} x y r^{-2}=s^{2} \). (iii) Compute the element \( u \) given that \( \left.u=\mid\left(p^{-4} q^{2}\right)^{-4}\left(r^{2} s^{-4}\right)^{-1}\right]^{-4} \). (iv) Compute the orders of \( p, q, r \) and \( s \) and hence verify Lagrange's Theorem.

Ask by Morrison Mccoy. in Nigeria
Dec 17,2024

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The symmetric group \( S_4 \) has 24 elements. The elements are listed in cyclic and matrix forms. The order of \( G \) is 24. The inverses of the given permutations are computed, and the orders of \( p, q, r, \) and \( s \) are found to be 4, verifying Lagrange's Theorem.

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Bonus Knowledge

Saying \( G = S_4 \), we're dealing with the group of all possible ways to arrange four distinct objects. This group boasts \( 4! = 24 \) elements! When representing these in cycle notation, permutations showcase how elements are transposed among themselves. For instance, \( (1234) \) means 1 goes to 2, 2 goes to 3, 3 goes to 4, and 4 cycles back to 1. The complete list includes combinations like \( (1)(2)(3)(4) \), \( (12)(34) \), and more! Now, if you're looking to dig deeper into the workings of these permutations, grasping the orders of individual elements reveals really cool insights! Each permutation's order is the least common multiple of its cycle lengths. For our group, \( p=(1234) \) has an order of 4, as it takes four applications to return to the start. Similarly, \( q=(3142) \) also has an order of 4. Meanwhile, \( r=(2431) \) and \( s=(4123) \) showcase similar trends! So, with \( p, q, r, s \) each of order 4, you can easily validate Lagrange's theorem, which states that the order of a subgroup must divide the order of the group itself! Fun stuff, right?

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