2. A box contains 3 red balls, 5 yellow balls, and 2 blue balls. If a ball is picked at random from the box, what is the probability that a ball picked is a a. yellow ball? b. red ball?

To determine the probabilities of picking a yellow or red ball from the box, we'll follow these steps: 1. **Calculate the total number of balls in the box.** 2. **Determine the number of favorable outcomes for each event (picking a yellow or red ball).** 3. **Use the probability formula:** \[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \] Let's apply these steps to each part of the problem. --- ### Given: - **Red balls:** 3 - **Yellow balls:** 5 - **Blue balls:** 2 **Total number of balls = 3 (Red) + 5 (Yellow) + 2 (Blue) = 10 balls** --- ### a. Probability of picking a **yellow** ball 1. **Number of favorable outcomes (yellow balls):** 5 2. **Total number of possible outcomes:** 10 \[ \text{Probability of yellow ball} = \frac{5}{10} = \frac{1}{2} \quad \text{or} \quad 50\% \] **Answer:** The probability of picking a yellow ball is \(\frac{1}{2}\) or 50%. --- ### b. Probability of picking a **red** ball 1. **Number of favorable outcomes (red balls):** 3 2. **Total number of possible outcomes:** 10 \[ \text{Probability of red ball} = \frac{3}{10} = 0.3 \quad \text{or} \quad 30\% \] **Answer:** The probability of picking a red ball is \(\frac{3}{10}\) or 30%. --- ### Summary: - **a. Yellow Ball:** \(\frac{1}{2}\) or 50% - **b. Red Ball:** \(\frac{3}{10}\) or 30%