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18 Una biglia viene lasciata cadere da \( 3,0 \mathrm{~m} \) di altezza ri- spetto al pavimento. Q Quanto tempo impiega per ragciungere il pavimento?

Ask by Bush Bob. in Italy
Jan 24,2025

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Answer

La biglia impiega circa 0,78 secondi per raggiungere il pavimento.

Solution

Per determinare il tempo necessario affinché una biglia cada da un'altezza di \( 3,0 \, \text{m} \) fino al pavimento, possiamo utilizzare le equazioni del moto uniformemente accelerato. Supponiamo che la biglia parta da ferma (\( v_0 = 0 \)) e che l'accelerazione sia dovuta alla gravità terrestre (\( g = 9,8 \, \text{m/s}^2 \)). L'equazione che descrive la distanza percorsa in caduta libera è: \[ h = \frac{1}{2} g t^2 \] Dove: - \( h \) è l'altezza (3,0 metri), - \( g \) è l'accelerazione di gravità (9,8 m/s²), - \( t \) è il tempo. Risolviamo per \( t \): \[ t^2 = \frac{2h}{g} \] \[ t = \sqrt{\frac{2h}{g}} \] Sostituendo i valori: \[ t = \sqrt{\frac{2 \times 3,0 \, \text{m}}{9,8 \, \text{m/s}^2}} = \sqrt{\frac{6,0}{9,8}} \approx \sqrt{0,612} \approx 0,782 \, \text{s} \] **Tempo impiegato:** circa **0,78 secondi**.

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Per calcolare il tempo impiegato dalla biglia per raggiungere il pavimento, possiamo utilizzare la formula del moto uniformemente accelerato: \[ h = \frac{1}{2} g t^2 \] dove \( h = 3,0 \, \mathrm{m} \) è l'altezza, \( g \approx 9,81 \, \mathrm{m/s^2} \) è l'accelerazione di gravità e \( t \) è il tempo in secondi. Risolvendo l'equazione per \( t \), otteniamo: \[ t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 \cdot 3,0}{9,81}} \approx 0,78 \, \mathrm{s} \] Quindi, la biglia impiega circa \( 0,78 \) secondi per toccare il pavimento. Immagina di lanciare quella biglia da un ponte: in quel momento, tempo e gravità si mettono d'accordo per offrirti un piccolo spettacolo! Il catechismo del moto cadente è tutto incentrato sull'idea di quanto la gravità possa essere potente e come influenzi il nostro quotidiano; questa esperienza offre un assaggio pratico di fisica in azione.

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