The graph below shows point P and line A . If line B is drawn such that it passes through point P and is parallel to line A , what is the equation of line Give your answer in the form \( y=m x+c \), where \( m \) and \( c \) are integers or fractions in their simplest forms.
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To find the equation of line B, which is parallel to line A and passes through point P, you need the slope of line A. Since parallel lines share the same slope, you can take the slope (m) of line A and apply it to line B. Then, using the coordinates of point P (let's say P has coordinates (x₁, y₁)), you can plug these values into the point-slope form of a line: \( y - y₁ = m(x - x₁) \). Rearranging this will give you \( y = mx + (y₁ - mx₁) \), where you can isolate c to find it. If line A has an equation like \( y = 2x + 3 \), then line B will also have a slope (m) of 2. If point P is (1, 4), you substitute to find \( y - 4 = 2(x - 1) \), simplifying to \( y = 2x + 2 \). Thus, the equation for line B will be \( y = 2x + 2 \).