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5) \( \log _{4}\left(a^{2} b^{2}\right) \)

Ask by Hampton Mills. in the United States
Jan 24,2025

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Answer

\( 2 \log_{4}a + 2 \log_{4}b \)

Solution

To simplify the logarithmic expression \( \log _{4}\left(a^{2} b^{2}\right) \), you can use the properties of logarithms, specifically the **Product Property** and the **Power Property**. 1. **Product Property**: \[ \log_b (MN) = \log_b M + \log_b N \] This allows you to separate the product inside the logarithm into the sum of two logarithms. 2. **Power Property**: \[ \log_b (M^k) = k \log_b M \] This allows you to bring the exponent in front of the logarithm. Applying these properties step by step: **Step 1: Apply the Product Property** \[ \log _{4}\left(a^{2} b^{2}\right) = \log_{4}(a^2) + \log_{4}(b^2) \] **Step 2: Apply the Power Property to Each Term** \[ \log_{4}(a^2) = 2 \log_{4}a \] \[ \log_{4}(b^2) = 2 \log_{4}b \] **Step 3: Combine the Results** \[ \log _{4}\left(a^{2} b^{2}\right) = 2 \log_{4}a + 2 \log_{4}b \] **Final Simplified Form:** \[ 2 \log_{4}a + 2 \log_{4}b \] This is the simplified form of the original logarithmic expression using logarithm properties.

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The Deep Dive

To simplify \( \log _{4}\left(a^{2} b^{2}\right) \), you can apply the product and power rules of logarithms. Using the product rule, this becomes \( \log_{4}(a^{2}) + \log_{4}(b^{2}) \). Next, applying the power rule, we can pull the exponent out: \( 2\log_{4}(a) + 2\log_{4}(b) \). So, the final simplified expression is \( 2(\log_{4}(a) + \log_{4}(b)) \). Don't forget, logarithms are all about relationships! The base of your log, in this case, is 4, which is \( 2^2 \). This means you can convert your logs to a base of 2 if you're ever in a pinch! Just remember, \( \log_{4}(x) = \frac{\log_{2}(x)}{\log_{2}(4)} \), and voilà! Your simplification can dance through different bases and reveal even deeper connections in your calculations.

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