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c. \( \sqrt{16} \cdot \sqrt{(-3)^{2}} \)

Ask by Cross Daniels. in Greece
Jan 16,2025

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\( \sqrt{16} \cdot \sqrt{(-3)^{2}} = 12 \)

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Mind Expander

Let's break this down! First off, \( \sqrt{16} = 4 \) because 4 times 4 equals 16. Now, for \( \sqrt{(-3)^2} \), squaring -3 gives us 9, and when you take the square root of 9, the answer is 3. So, if we multiply those results together, we get \( 4 \cdot 3 = 12 \). Voilà, the final answer is 12! Here's a fun fact: the property of square roots states that \( \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} \), as long as both \( a \) and \( b \) are non-negative. This makes simplifying expressions much easier! Also, remember that even though we dealt with \((-3)^2\) to ultimately get a positive number under the square root, always keep in mind that the principal square root typically denotes the non-negative root. This is a common misconception that can lead to confusion!

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