Solve the following inequality for \( x \). \[ a x+5>13 \] A \( x>8-a \) B \( x<\frac{8}{a} \) C \( x>\frac{a}{8} \) D \( x>\frac{8}{a} \)

To solve the inequality \( a x + 5 > 13 \), we start by isolating \( x \). 1. Subtract 5 from both sides: \[ a x > 8 \] 2. Now, divide both sides by \( a \) (assuming \( a > 0 \) for the moment; we'll discuss the case when \( a < 0 \) afterwards): \[ x > \frac{8}{a} \] Now, if \( a < 0 \), when we divide by \( a \), the inequality sign reverses, leading to: \[ x < \frac{8}{a} \] Thus, the solution can depend on the value of \( a \). However, if we consider just the scenario where \( a > 0 \), the correct expression is: \[ \boxed{D} \quad x > \frac{8}{a} \] If \( a < 0 \), it would correspond to: \[ x < \frac{8}{a} \] But since our options only account for the first scenario, we select \( D \) as the answer.