\( 7 \quad 3 x-5<5 x-3 \) [WAEC]

To solve the inequality \( 3x - 5 < 5x - 3 \), start by getting all the \( x \) terms on one side. Subtract \( 3x \) from both sides, giving you \( -5 < 2x - 3 \). Next, add \( 3 \) to both sides to isolate the term with \( x \): \( -2 < 2x \). Now, divide both sides by \( 2 \), which results in \( -1 < x \) or in a more common form, \( x > -1 \). This means that any number greater than \(-1\) is a solution to the inequality, so feel free to plug in some numbers greater than \(-1\) to see if they satisfy the inequality!