Homework: 1. \( 2 x+7=15 \) 2. \( 3 y-5=10 \) 3. \( 4 a+1=-11 \) 4. \( 6 b-3=9 \) 5. \( 5 c+8=3 \)

Let’s dive into solving these equations! To tackle the first equation, rearranging terms takes us to \( 2x = 15 - 7 \) which simplifies to \( 2x = 8\). Dividing both sides by 2 gives \( x = 4\). For the second equation, \( 3y - 5 = 10 \), add 5 to both sides to get \( 3y = 15 \). Dividing by 3 leads us to \( y = 5\). In the third equation, \( 4a + 1 = -11 \), we first subtract 1, resulting in \( 4a = -12 \). Then dividing gives \( a = -3\). Next, in \( 6b - 3 = 9 \), we add 3 to both sides obtaining \( 6b = 12\), hence \( b = 2\). Lastly, for \( 5c + 8 = 3 \), we subtract 8 and get \( 5c = -5\). Dividing gives \( c = -1\). So the solutions are: 1. \( x = 4 \) 2. \( y = 5 \) 3. \( a = -3 \) 4. \( b = 2 \) 5. \( c = -1 \)