c. The diagonal \( A C \) has the equation \( y=x+5 \). Find the point of intersection of the two diagonals \( A C \) and \( B D \).

To find the point of intersection of the two diagonals \( A C \) and \( B D \), we first need the equation of diagonal \( B D \). Assuming \( B D \) can be expressed in the standard line form \( y = mx + b \), we can start by rewriting the equation of diagonal \( A C \), which you provided as \( y = x + 5 \). Next, let's assume both diagonals intersect. We need to set the equation of diagonal \( B D \) equal to that of diagonal \( A C \): 1. Let’s say the equation of diagonal \( B D \) has the form \( y = mx + b \). 2. Set it equal to \( y = x + 5 \). Hence, this gives us: \[ mx + b = x + 5 \] To find the intersection point, we need to express both equations together, which ultimately leads to us solving for \( x \) and then substituting back to find \( y \). However, without additional specific information (coordinates for points, slopes for the other diagonal, etc.), we can't determine the exact point of intersection. Could you provide more details about diagonal \( B D \)?