Question 10 ( 3 points) The centre-to-centre distance of two pulleys is 28.6875 inches. Pulley "A" measures 6.954 inches on the O.D. of the flange and Pulley "B" measures 4.743 inches on the O.D. of the flange. What is the inside-to-inside measurement between the two pulley flanges expressed in feet and inches to the nearest 16 th?

To find the inside-to-inside measurement between the two pulley flanges, subtract the outer diameter measurements from the centre-to-centre distance. First, convert the diameters from inches to feet for easier calculations later: 1. Convert O.D. of Pulley "A": 6.954 inches = 0.5795 feet (6.954/12). 2. Convert O.D. of Pulley "B": 4.743 inches = 0.39525 feet (4.743/12). Now calculate the inside-to-inside distance using the formula: Inside Distance = Centre Distance - (O.D. of A + O.D. of B) = 28.6875 - (6.954 + 4.743) = 28.6875 - 11.697 ≈ 16.9905 inches. Now, convert this to feet and inches. 16.9905 inches is 1 foot 4.9905 inches, which we round to the nearest 16th. This is approximately 1 foot 5 inches. In conclusion, the inside-to-inside measurement between the two pulley flanges is roughly 1 foot 5 inches.