\( \int \ln ( \sqrt { x } + \sqrt { x + 1 } ) d x \)
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Mind Expander
To tackle the integral \( \int \ln ( \sqrt { x } + \sqrt { x + 1 } ) d x \), let's consider a substitution that simplifies our integrand. Notice that the expression \( \sqrt{x} + \sqrt{x+1} \) is closely related to the structure of the original variable under the integral. One effective approach is to let \( u = \sqrt{x} + \sqrt{x+1} \). Differentiating both sides with respect to \( x \) helps us to link \( dx \) to \( du \). With some algebra, also keep in mind to rewrite the integral in terms of this new variable, which may involve finding \( x \) in terms of \( u \) as well. Moreover, when performing such integrals, common pitfalls include losing track of constant factors when substituting or not properly transforming \( dx \). Keep those calculations clear, and you’re bound to have a smooth process through this integral!