Solve the system by substitution: \[ \begin{array}{l}5 \mathrm{x}+4 \mathrm{y}=-14 \\ \mathrm{y}=-7 \mathrm{x}-15\end{array} \]
Real Tutor Solution
Answer
Solution
Reviewed and approved by the UpStudy tutoring team
Beyond the Answer
To solve the system using substitution, we can plug the expression for \(y\) from the second equation into the first equation. So, we have: 1. First equation: \(5x + 4y = -14\) 2. Second equation: \(y = -7x - 15\) Now, substitute the expression for \(y\) into the first equation: \[ 5x + 4(-7x - 15) = -14 \] Now simplify the equation: \[ 5x - 28x - 60 = -14 \] \[ -23x - 60 = -14 \] Next, add 60 to both sides: \[ -23x = 46 \] Now, divide both sides by -23: \[ x = -2 \] Now that we have \(x\), let's find \(y\) using the second equation: \[ y = -7(-2) - 15 \] \[ y = 14 - 15 \] \[ y = -1 \] Thus, the solution to the system of equations is: \[ (x, y) = (-2, -1) \]