Answer
The graph of \( h = 10t - t^{2} \) is a downward-opening parabola with its vertex at \( (5, 25) \). It crosses the t-axis at \( t = 0 \) and \( t = 10 \).
Solution
Certainly! Let's analyze and graph the quadratic relationship \( h = 10t - t^{2} \).
### 1. Understanding the Equation
The equation \( h = 10t - t^{2} \) is a quadratic equation in the form:
\[ h = -t^{2} + 10t \]
This represents a parabola that opens **downward** because the coefficient of \( t^{2} \) is negative.
### 2. Key Features of the Graph
#### a. **Vertex**
The vertex of a parabola \( h = at^{2} + bt + c \) occurs at:
\[ t = -\frac{b}{2a} \]
For \( h = -t^{2} + 10t \):
- \( a = -1 \)
- \( b = 10 \)
So,
\[ t = -\frac{10}{2(-1)} = 5 \]
To find the corresponding \( h \)-value:
\[ h = 10(5) - (5)^2 = 50 - 25 = 25 \]
**Vertex:** \( (5, 25) \)
#### b. **Axis of Symmetry**
The axis of symmetry is the vertical line that passes through the vertex:
\[ t = 5 \]
#### c. **Intercepts**
- **T-intercepts (where \( h = 0 \)):**
Set \( h = 0 \):
\[ 0 = 10t - t^{2} \]
\[ t^{2} - 10t = 0 \]
\[ t(t - 10) = 0 \]
So, \( t = 0 \) and \( t = 10 \).
**T-intercepts:** \( (0, 0) \) and \( (10, 0) \)
- **H-intercept (where \( t = 0 \)):**
When \( t = 0 \), \( h = 0 \).
**H-intercept:** \( (0, 0) \) (same as one of the t-intercepts)
#### d. **Direction of Opening**
Since the coefficient of \( t^{2} \) is negative (\( a = -1 \)), the parabola opens **downward**.
### 3. Table of Values
| \( t \) | \( h = 10t - t^{2} \) |
|---------|-----------------------|
| 0 | 0 |
| 1 | 10(1) - 1 = 9 |
| 2 | 20 - 4 = 16 |
| 3 | 30 - 9 = 21 |
| 4 | 40 - 16 = 24 |
| 5 | 50 - 25 = 25 |
| 6 | 60 - 36 = 24 |
| 7 | 70 - 49 = 21 |
| 8 | 80 - 64 = 16 |
| 9 | 90 - 81 = 9 |
| 10 | 100 - 100 = 0 |
### 4. Sketching the Graph
Using the key features and the table of values, here's a step-by-step guide to sketch the graph:
1. **Plot the Vertex:** \( (5, 25) \).
2. **Plot the T-intercepts:** \( (0, 0) \) and \( (10, 0) \).
3. **Draw the Axis of Symmetry:** A vertical dashed line through \( t = 5 \).
4. **Plot Additional Points:** Use the table above to plot points like \( (2, 16) \), \( (3, 21) \), etc.
5. **Connect the Points:** Draw a smooth, downward-opening parabola passing through all the points.
### 5. Graph Representation
While I can't provide a visual graph directly, here's a rough sketch using text:
```
h
|
25| *
20| * *
15| * *
10| * *
5 | * *
0 |*---------------------*----- t
0 2 4 5 6 8 10
```
- The highest point is at \( (5, 25) \).
- The parabola crosses the \( t \)-axis at \( t = 0 \) and \( t = 10 \).
### 6. Interpretation
This quadratic relationship could represent, for example, the height \( h \) of an object in meters at time \( t \) seconds if it's thrown upwards with an initial velocity, considering gravity's effect.
### 7. Summary of Key Points
- **Vertex:** \( (5, 25) \)
- **Axis of Symmetry:** \( t = 5 \)
- **T-intercepts:** \( t = 0 \) and \( t = 10 \)
- **Opening Direction:** Downward
This comprehensive analysis should help you visualize and understand the graph of the equation \( h = 10t - t^{2} \).
Reviewed and approved by the UpStudy tutoring team
Explain
Simplify this solution