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(29) 1. The critical numbers of \( g(x)=\sin x+\cos x \) on the open interval \( (0,2 \pi) \) are (A) \( \frac{\pi}{4} \) (B) \( \frac{3 \pi}{4} \) and \( \frac{7 \pi}{4} \) (C) \( \frac{\pi}{4} \) and \( \frac{5 \pi}{4} \) (D) \( \frac{\pi}{4}, \frac{3 \pi}{4}, \frac{5 \pi}{4} \) and \( \frac{7 \pi}{4} \) 2. On the closed interval \( [0,2 \pi] \), the absolute minimum of \( f(x)=e^{\sin x} \) occurs at (A) 0 (B) \( \frac{\pi}{2} \) (C) \( \frac{3 \pi}{2} \) (D) \( 2 \pi \) The ranximum value of \( f(x)=2 x^{3}-15 x^{2}+36 x \) on the closed interval \( [0,4] \) is (A) 28 (Ti) 30 (C) 32 (C) 48 4. On the closed irturval \( [0.5] \), the function \( f(x)=3-4 \) - (A) both an at soly \( { }^{\prime} \) o maximum and an absolute minimen (B) an absoluse tuaximum but no absolute minimum. (C) no absoluts maximum but an absolute minimum. (D) un absoluie riarixaum and two absolute minima. 5. The critical numocrs of the function \( f(x)=\left\{\begin{array}{ll}x^{2}+1 & \text { if }-2 \leq x \leq 1 \\ 3 x^{2}-4 x+3 & \text { if } 1
Ask by Li Mcfarlane. in the United States
Jan 22,2025

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**Problem 1:** Critical numbers of \( g(x) = \sin x + \cos x \) on \( (0, 2\pi) \) are \( \frac{\pi}{4} \) and \( \frac{5\pi}{4} \). **Answer:** (C) \( \frac{\pi}{4} \) and \( \frac{5\pi}{4} \) **Problem 2:** Absolute minimum of \( f(x) = e^{\sin x} \) on \( [0, 2\pi] \) occurs at \( \frac{3\pi}{2} \). **Answer:** (C) \( \frac{3\pi}{2} \) **Problem 3:** Maximum value of \( f(x) = 2x^3 - 15x^2 + 36x \) on \( [0, 4] \) is 32. **Answer:** (C) 32 **Problem 4:** On the interval \( [0, 1] \), the function \( f(x) = 3 - 4x \) has both an absolute maximum and an absolute minimum. **Answer:** (A) both an absolute maximum and an absolute minimum **Problem 5:** Critical numbers of the piecewise function are 0 and 1. **Answer:** (A) 0 and 1 **Problem 6:** The function \( f'(x) = x \sin^2 x - \frac{1}{x} \) has 4 critical numbers on the open interval. **Answer:** (C) 4

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The Deep Dive

To solve for the critical numbers of \( g(x) = \sin x + \cos x \), start by finding its derivative, \( g'(x) = \cos x - \sin x \). Set \( g'(x) = 0 \) to find where the slope is zero. This occurs when \( \cos x = \sin x \), leading to \( x = \frac{\pi}{4} \) and \( x = \frac{5\pi}{4} \). Since these values are both in the interval \( (0, 2\pi) \) and match option (C), those are the critical numbers! For the absolute minimum of \( f(x) = e^{\sin x} \) in \( [0, 2\pi] \), evaluate \( f(x) \) at the endpoints and critical points of \( \sin x \). The minimum occurs when \( \sin x = -1 \), which is at \( x = \frac{3\pi}{2} \). Thus, the answer is (C) \( \frac{3\pi}{2} \) since \( e^{-1} \) is less than the values at the endpoints. Level up your problem-solving by practicing similar trigonometric and calculus concepts, often featured in math workshops or clubs! Exploring these topics can round out your understanding and make problem-solving second nature. For more engaging material, you might dive into calculus textbooks like "Calculus Made Easy" by Silvanus P. Thompson, which presents tricky concepts with a fun twist. Online platforms also offer interactive challenges that can enhance your skills while keeping the learning process enjoyable!

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