Question
(e) Consider the geometric sequence
(1) Calculate the sum of the first 10 terms of the sequence.
(2) How many terms in this sequence will add up to
?
(3) Determine the smallest value of
for which
.
(1) Calculate the sum of the first 10 terms of the sequence.
(2) How many terms in this sequence will add up to
(3) Determine the smallest value of
Ask by Gough Elliott. in South Africa
Jan 24,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
- The sum of the first 10 terms is 767.25.
- 12 terms add up to 3071.25.
- The smallest value of
for which is 11.
Solution
Let’s analyze the given geometric sequence and solve each part step by step.
Given Sequence:
Common Ratio (
):
To find the common ratio
, divide the second term by the first term:
Thus, the sequence is:
(1) Sum of the First 10 Terms (
):
The sum of the first
terms of a geometric sequence is given by:
where
,
, and
.
Plugging in the values:
(2) Number of Terms Adding Up to
(
):
Set the sum formula equal to
:
Multiply both sides by 4:
Divide by 3:
Add 1:
Recognizing that
, we find:
(3) Smallest
for Which
:
We need to find the smallest
such that:
Multiply both sides by
:
Add 1:
Determine the smallest
where
exceeds 1334.33:
Thus, the smallest
is:
Final Answers:
- The sum of the first 10 terms is
. - 12 terms add up to
. - The smallest value of
for which is 11.
Answered by UpStudy AI and reviewed by a Professional Tutor
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The Deep Dive
To solve the problem, let’s break it down step by step!
(1) Calculate the sum of the first 10 terms of the sequence.
The given sequence is a geometric sequence where the first term
and the common ratio
.
The sum of the first
terms of a geometric series is given by the formula:
Substituting for
:
Thus, the sum of the first 10 terms is
.
(2) How many terms in this sequence will add up to
?
Using the sum formula
again, equate it to
:
This simplifies to:
Multiplying both sides by 4:
Thus,
. Therefore, 12 terms in this sequence will add up to
.
(3) Determine the smallest value of
for which
.
Using the sum formula again, we want to find
such that:
Substituting into the formula:
This simplifies to:
Multiplying by
(remembering to flip the inequality):
Since
is always positive, we only need to solve for:
Taking the logarithm base 2 of both sides, we find:
Thus the smallest integer
.
So the smallest value of
such that
is
.