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A bacteria population is 10,000 . It triples each day. The bacteria population, \( b \), is a function of the number of days, \( d \), since it was measured to be 10,000 . 1. Which variable is the independent variable in this situation? 2. Write an equation relating \( b \) and \( d \).

Ask by Fitzgerald Perkins. in the United States
Jan 22,2025

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Answer

1. **Independent Variable:** The number of days, \( d \). 2. **Equation Relating \( b \) and \( d \):** \[ b = 10,\!000 \times 3^{d} \]

Solution

1. **Independent Variable:** The independent variable is the number of days, \( d \). This is because \( d \) is the variable you control or change to observe its effect on the bacteria population. 2. **Equation Relating \( b \) and \( d \):** \[ b = 10,\!000 \times 3^{d} \] **Explanation:** - The initial bacteria population is 10,000. - The population triples each day, which is represented by the base 3 in the exponential equation. - \( d \) represents the number of days, serving as the exponent to show how many times the population has tripled. So, for each day that passes, the population multiplies by 3. For example: - After 1 day: \( b = 10,\!000 \times 3^{1} = 30,\!000 \) - After 2 days: \( b = 10,\!000 \times 3^{2} = 90,\!000 \) - After 3 days: \( b = 10,\!000 \times 3^{3} = 270,\!000 \) And so on.

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Beyond the Answer

In this situation, the independent variable is the number of days, \( d \), because it is the variable that you control or manipulate to observe its effect on the bacteria population. As days go by, you measure how the population changes. To relate the bacteria population \( b \) to the number of days \( d \), we can use the formula \( b = 10,000 \cdot 3^d \). This equation shows that the initial population of 10,000 triples every day, leading to explosive growth as days progress! So, if you want to find out how many bacteria will be present after a certain number of days, just plug in the value of \( d \)!

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