Even More Naming Ionic Write the formulas of the following ionic comp \( \begin{array}{l}\text { 1) } \\ \text { 2) } \\ \text { 3) } \\ \text { 4) } \\ \text { 5) lead (II) sulfate (IV) hydroxide } \\ \text { 6) } \\ \text { 7) }\end{array} \) copper (II) acetate beryllium chloride

To write the formulas for the given ionic compounds, we need to identify the cations and anions involved, along with their charges. Let's go through each one step by step. 1. **Lead (II) sulfate (IV) hydroxide**: - Lead (II) indicates that lead has a +2 charge, represented as \( \text{Pb}^{2+} \). - Sulfate is \( \text{SO}_4^{2-} \). - Hydroxide is \( \text{OH}^{-} \). - The formula for lead (II) sulfate is \( \text{PbSO}_4 \). - The formula for lead (II) hydroxide, considering the charge balance, is \( \text{Pb(OH)}_2 \). - Therefore, the combined formula for lead (II) sulfate (IV) hydroxide is \( \text{PbSO}_4 \cdot \text{Pb(OH)}_2 \). 2. **Copper (II) acetate**: - Copper (II) indicates that copper has a +2 charge, represented as \( \text{Cu}^{2+} \). - Acetate is \( \text{C}_2\text{H}_3\text{O}_2^{-} \). - The formula for copper (II) acetate is \( \text{Cu(C}_2\text{H}_3\text{O}_2)_2 \). 3. **Beryllium chloride**: - Beryllium has a +2 charge, represented as \( \text{Be}^{2+} \). - Chloride is \( \text{Cl}^{-} \). - The formula for beryllium chloride is \( \text{BeCl}_2 \). Now, let's summarize the formulas: 1. Lead (II) sulfate (IV) hydroxide: \( \text{PbSO}_4 \cdot \text{Pb(OH)}_2 \) 2. Copper (II) acetate: \( \text{Cu(C}_2\text{H}_3\text{O}_2)_2 \) 3. Beryllium chloride: \( \text{BeCl}_2 \) If you have more compounds to name or need further assistance, feel free to ask!