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0. \( \quad 2(8 p-3 q)\left(p-3+q^{2}\right) \)

Ask by Hall Frank. in South Africa
Jan 25,2025

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Tutor-Verified Answer

Answer

The expanded form of the expression \( 2(8p - 3q)(p - 3 + q^{2}) \) is: \[ 16p^{2} - 48p + 16p q^{2} - 6p q + 18q - 6q^{3} \]

Solution

To expand the expression: \[ 2(8p - 3q)\left(p - 3 + q^{2}\right) \] follow these steps: ### Step 1: Expand the Inner Product First, expand the product \((8p - 3q)(p - 3 + q^{2})\): \[ (8p - 3q)(p - 3 + q^{2}) = 8p \cdot p + 8p \cdot (-3) + 8p \cdot q^{2} - 3q \cdot p - 3q \cdot (-3) - 3q \cdot q^{2} \] Calculate each term: \[ \begin{align*} 8p \cdot p &= 8p^{2} \\ 8p \cdot (-3) &= -24p \\ 8p \cdot q^{2} &= 8p q^{2} \\ -3q \cdot p &= -3p q \\ -3q \cdot (-3) &= 9q \\ -3q \cdot q^{2} &= -3q^{3} \\ \end{align*} \] Combine all the terms: \[ 8p^{2} - 24p + 8p q^{2} - 3p q + 9q - 3q^{3} \] ### Step 2: Multiply by 2 Now, multiply the entire expression by 2: \[ 2 \times (8p^{2} - 24p + 8p q^{2} - 3p q + 9q - 3q^{3}) = 16p^{2} - 48p + 16p q^{2} - 6p q + 18q - 6q^{3} \] ### Final Expanded Form The fully expanded form of the original expression is: \[ 16p^{2} - 48p + 16p q^{2} - 6p q + 18q - 6q^{3} \]

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Mind Expander

Did you know that the expression you're working with can be simplified beautifully? If you distribute \(2(8p - 3q)\) across \((p - 3 + q^2)\), you'll discover that it expands into a mix of polynomial terms. This process showcases the fundamentals of algebraic manipulation, where the distributive property reigns supreme. Just remember, when multiplying, every term from the first expression needs to be paired with every term in the second—it's like a dance! Now, did you know that similar expressions arise in real-life situations like calculating areas or volumes in geometry? For instance, if you were to model the volume of a container whose dimensions can be represented as polynomials, such expressions become crucial. Mastering these products will empower you to tackle complex problems in architecture, engineering, and even economics where multi-variable expressions are common!

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