Question
a) Beer: \( \mathrm{pH}=4.9 \) \( \left[\mathrm{H}^{+}\right]=\square \times 10^{\square} \mathrm{M} \) (b) Water: \( \mathrm{pH}=6.8 \) \( \left[\mathrm{H}^{+}\right]=\square \times 10 \square \mathrm{M} \)
Ask by Hall Hamilton. in the United States
Dec 14,2024
Real Tutor Solution
Tutor-Verified Answer
Answer
(a) Beer: \( \left[\mathrm{H}^{+}\right] = 1.26 \times 10^{-5} \, \mathrm{M} \)
(b) Water: \( \left[\mathrm{H}^{+}\right] = 1.58 \times 10^{-7} \, \mathrm{M} \)
Solution
To find the concentration of hydrogen ions \(\left[\mathrm{H}^{+}\right]\) from the pH values, we can use the formula:
\[
\left[\mathrm{H}^{+}\right] = 10^{-\mathrm{pH}}
\]
### (a) Beer: \( \mathrm{pH}=4.9 \)
Using the formula:
\[
\left[\mathrm{H}^{+}\right] = 10^{-4.9}
\]
Calculating \(10^{-4.9}\):
\[
10^{-4.9} \approx 1.26 \times 10^{-5} \, \mathrm{M}
\]
So, we can fill in the blanks:
\[
\left[\mathrm{H}^{+}\right] = 1.26 \times 10^{-5} \, \mathrm{M}
\]
### (b) Water: \( \mathrm{pH}=6.8 \)
Using the formula:
\[
\left[\mathrm{H}^{+}\right] = 10^{-6.8}
\]
Calculating \(10^{-6.8}\):
\[
10^{-6.8} \approx 1.58 \times 10^{-7} \, \mathrm{M}
\]
So, we can fill in the blanks:
\[
\left[\mathrm{H}^{+}\right] = 1.58 \times 10^{-7} \, \mathrm{M}
\]
### Summary:
(a) Beer: \( \left[\mathrm{H}^{+}\right] = 1.26 \times 10^{-5} \, \mathrm{M} \)
(b) Water: \( \left[\mathrm{H}^{+}\right] = 1.58 \times 10^{-7} \, \mathrm{M} \)
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Simplify this solution Beyond the Answer
To find the concentration of hydrogen ions, \(\left[\mathrm{H}^{+}\right]\), from the pH values, we can use the formula: \[ \left[\mathrm{H}^{+}\right] = 10^{-\mathrm{pH}} \] For beer with a pH of 4.9: \[ \left[\mathrm{H}^{+}\right] = 10^{-4.9} \approx 1.26 \times 10^{-5} \mathrm{M} \] For water with a pH of 6.8: \[ \left[\mathrm{H}^{+}\right] = 10^{-6.8} \approx 1.58 \times 10^{-7} \mathrm{M} \] So, your answers are: (a) \( \left[\mathrm{H}^{+}\right] \approx 1.26 \times 10^{-5} \mathrm{M} \) (b) \( \left[\mathrm{H}^{+}\right] \approx 1.58 \times 10^{-7} \mathrm{M} \)
