A rectangular field is seven times as long as it is wide. If the perimeter of the field is 1040 feet, what are the dimensions of the field? The width of the field is The length of the field is $$ $$ feet. Next Question

Question

A rectangular field is seven times as long as it is wide. If the perimeter of the field is 1040 feet, what are the dimensions of the field? The width of the field is The length of the field is $$ > $$ feet. Next Question

UpStudy AI · Accepted Answer

To determine the dimensions of the rectangular field, let's follow these steps:

1. **Define the Variables:**
   - Let $$ w $$ be the width of the field.
   - Since the length is seven times the width, the length $$ l $$ is $$ 7w $$.

2. **Use the Perimeter Formula:**
   The perimeter $$ P $$ of a rectangle is given by:
   $$
   P = 2 \times (\text{length} + \text{width})
   $$
   Plugging in the known values:
   $$
   1040 = 2 \times (7w + w)
   $$
   
3. **Solve for $$ w $$:**
   $$
   1040 = 2 \times 8w \
   1040 = 16w \
   w = \frac{1040}{16} \
   w = 65 \text{ feet}
   $$

4. **Determine the Length:**
   $$
   l = 7w = 7 \times 65 = 455 \text{ feet}
   $$

**Final Dimensions:**
- **Width of the field:** $$ 65 $$ feet
- **Length of the field:** $$ 455 $$ feet
The width of the field is 65 feet, and the length is 455 feet.

A rectangular field is seven times as long as it is wide. If the perimeter of the field is 1040 feet, what are the dimensions of the field? The width of the field is The length of the field is \( > \) feet. Next Question

Real Tutor Solution

Answer

Solution

Bonus Knowledge

Related Questions

Latest Algebra Questions