What is the balanced form of the chemical equation shown below? \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{H}_{2} \mathrm{O}(\rho)+\mathrm{CO}_{2}(g) \) A. \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{H}_{2} \mathrm{O}(t)+\mathrm{CO}_{2}(g) \) B. \( \mathrm{CH}_{2} \mathrm{O}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{H}_{2} \mathrm{O}(\rho)+\mathrm{CO}_{2}(g) \) C. \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+\mathrm{O}_{2}(g) \rightarrow 12 \mathrm{H}_{2} \mathrm{O}(\rho)+6 \mathrm{CO}_{2}(g) \) D. \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+6 \mathrm{O}_{2}(g) \rightarrow 6 \mathrm{H}_{2} \mathrm{O}(\rho)+6 \mathrm{CO}_{2}(g) \)
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Bonus Knowledge
The balanced form of the chemical equation for the combustion of glucose is D: \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+6 \mathrm{O}_{2}(g) \rightarrow 6 \mathrm{H}_{2} \mathrm{O}(\rho)+6 \mathrm{CO}_{2}(g) \). In this equation, one molecule of glucose reacts with six molecules of oxygen to produce six molecules of water and six molecules of carbon dioxide, ensuring that the number of each type of atom on both sides of the equation is equal. Combustion of glucose isn't just a textbook reaction—it fuels life! In the human body, glucose is converted to energy through cellular respiration. This balanced equation expresses the process that occurs in our cells, where glucose and oxygen get transformed into energy, carbon dioxide, and water, highlighting the fundamental relationship between food and energy in living organisms.