\( \triangle K A T \) is congruent to \( \triangle X Y Z \) In \( \Delta Y Y Z, ~ \) I \( =45^{\circ} \) and in \( \triangle K A T ~ \) \( A A= \) \( 78^{\circ} \). Find the measure of \( \measuredangle Z \).
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Since \( \triangle KAT \) is congruent to \( \triangle XYZ \), the corresponding angles are also congruent. Given that \( \angle A = 78^\circ \) in \( \triangle KAT \), the angle \( \angle Y \) in \( \triangle XYZ \) must also be \( 78^\circ \). We also know that \( \angle I = 45^\circ \) in \( \triangle YYZ \). To find \( \angle Z \), we can use the fact that the sum of the interior angles in any triangle is \( 180^\circ \). Thus, we have: \[ \angle Y + \angle I + \angle Z = 180^\circ \] Substituting the known values: \[ 78^\circ + 45^\circ + \angle Z = 180^\circ \] Combining the angles: \[ 123^\circ + \angle Z = 180^\circ \] Now, subtract \( 123^\circ \) from both sides: \[ \angle Z = 180^\circ - 123^\circ = 57^\circ \] Therefore, the measure of \( \angle Z \) is \( 57^\circ \).