Simplify this expression: $$ 7(y+z) $$ $$ \begin{array}{ll} ext { A. } 7 y z & ext { B. } 7 y+z \ ext { C. } 7 y+7 z & ext { D. } 7 z+y\end{array} $$

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Simplify this expression: $$ 7(y+z) $$ $$ \begin{array}{ll}	ext { A. } 7 y z & 	ext { B. } 7 y+z \ 	ext { C. } 7 y+7 z & 	ext { D. } 7 z+y\end{array} $$

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To simplify the expression $$ 7(y + z) $$, you can use the **distributive property** of multiplication over addition. This property states that $$ a(b + c) = ab + ac $$.

Applying this to your expression:

$$
7(y + z) = 7 \cdot y + 7 \cdot z = 7y + 7z
$$

**Therefore, the simplified expression is:**

**C. $$ 7y + 7z $$**
The simplified expression is $$ 7y + 7z $$, choice C.

Simplify this expression: \( 7(y+z) \) \( \begin{array}{ll}\text { A. } 7 y z & \text { B. } 7 y+z \\ \text { C. } 7 y+7 z & \text { D. } 7 z+y\end{array} \)

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