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(c)) \( \frac{y-2}{2}-\frac{y+1}{3}=\frac{1}{4} \)

Ask by May Barrett. in Indonesia
Jan 23,2025

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Answer

\( y = \frac{19}{2} \) or \( y = 9.5 \)

Solution

Untuk menyelesaikan persamaan: \[ \frac{y - 2}{2} - \frac{y + 1}{3} = \frac{1}{4} \] Ikuti langkah-langkah berikut: ### Langkah 1: Mencari Penyebut Umum Penyebut umum terkecil (KPK) dari 2, 3, dan 4 adalah 12. Kalikan kedua sisi persamaan dengan 12 untuk menghilangkan pecahan. \[ 12 \times \left( \frac{y - 2}{2} - \frac{y + 1}{3} \right) = 12 \times \frac{1}{4} \] ### Langkah 2: Mengalikan dan Menyederhanakan \[ 12 \times \frac{y - 2}{2} - 12 \times \frac{y + 1}{3} = 12 \times \frac{1}{4} \] \[ 6(y - 2) - 4(y + 1) = 3 \] ### Langkah 3: Mengembangkan \[ 6y - 12 - 4y - 4 = 3 \] ### Langkah 4: Menggabungkan Suku yang Sama \[ (6y - 4y) + (-12 - 4) = 3 \] \[ 2y - 16 = 3 \] ### Langkah 5: Menyelesaikan untuk \( y \) Tambahkan 16 ke kedua sisi: \[ 2y = 3 + 16 \] \[ 2y = 19 \] Bagikan kedua sisi dengan 2: \[ y = \frac{19}{2} \] \[ y = 9.5 \] ### Kesimpulan Nilai dari \( y \) yang memenuhi persamaan tersebut adalah: \[ y = \frac{19}{2} \quad \text{atau} \quad y = 9.5 \]

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To solve the equation \( \frac{y-2}{2}-\frac{y+1}{3}=\frac{1}{4} \), we start by finding a common denominator. The least common multiple of 2, 3, and 4 is 12. We can rewrite each term with a denominator of 12: \[ \frac{6(y-2)}{12} - \frac{4(y+1)}{12} = \frac{3}{12} \] Now, multiply the entire equation by 12 to eliminate the denominators: \[ 6(y-2) - 4(y+1) = 3 \] Distributing gives us: \[ 6y - 12 - 4y - 4 = 3 \] Combining like terms: \[ 2y - 16 = 3 \] Add 16 to both sides: \[ 2y = 19 \] Now, divide by 2 to find \(y\): \[ y = \frac{19}{2} \quad \text{or} \quad y = 9.5 \] And there you have it! The solution to the equation is \(y = 9.5\).

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