(c)) \( \frac{y-2}{2}-\frac{y+1}{3}=\frac{1}{4} \)
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To solve the equation \( \frac{y-2}{2}-\frac{y+1}{3}=\frac{1}{4} \), we start by finding a common denominator. The least common multiple of 2, 3, and 4 is 12. We can rewrite each term with a denominator of 12: \[ \frac{6(y-2)}{12} - \frac{4(y+1)}{12} = \frac{3}{12} \] Now, multiply the entire equation by 12 to eliminate the denominators: \[ 6(y-2) - 4(y+1) = 3 \] Distributing gives us: \[ 6y - 12 - 4y - 4 = 3 \] Combining like terms: \[ 2y - 16 = 3 \] Add 16 to both sides: \[ 2y = 19 \] Now, divide by 2 to find \(y\): \[ y = \frac{19}{2} \quad \text{or} \quad y = 9.5 \] And there you have it! The solution to the equation is \(y = 9.5\).