2. Mr, Perez built this circular garden. The inner circle has a diameter of 22 feet. The outer circle has a diameter of 44 feet. What is the area of section \( B \) ? Explain your answer.

To determine the area of section \( B \) in Mr. Perez's circular garden, we'll analyze the information provided: 1. **Understanding the Structure:** - **Inner Circle:** Diameter = 22 feet ⇒ Radius = \( \frac{22}{2} = 11 \) feet - **Outer Circle:** Diameter = 44 feet ⇒ Radius = \( \frac{44}{2} = 22 \) feet It's reasonable to assume that **section \( B \)** refers to the **annular region** (the ring-shaped area) between the inner and outer circles. 2. **Calculating the Areas:** - **Area of the Outer Circle (\( A_{\text{outer}} \)):** \[ A_{\text{outer}} = \pi \times (\text{Radius}_{\text{outer}})^2 = \pi \times 22^2 = 484\pi \text{ square feet} \] - **Area of the Inner Circle (\( A_{\text{inner}} \)):** \[ A_{\text{inner}} = \pi \times (\text{Radius}_{\text{inner}})^2 = \pi \times 11^2 = 121\pi \text{ square feet} \] 3. **Determining the Area of Section \( B \):** The area of section \( B \) (the annulus) is the difference between the area of the outer circle and the area of the inner circle: \[ A_B = A_{\text{outer}} - A_{\text{inner}} = 484\pi - 121\pi = 363\pi \text{ square feet} \] 4. **Final Answer:** The area of section \( B \) is \( \mathbf{363\pi} \) square feet. If you prefer a numerical approximation, using \( \pi \approx 3.1416 \): \[ A_B \approx 363 \times 3.1416 \approx 1,\!141.56 \text{ square feet} \] **Conclusion:** Section \( B \) occupies an area of \( 363\pi \) square feet, which represents the space between the inner and outer circles of the garden.