\begin{tabular}{|ll} 2. Which are the factors of \( x^{2}+7 x-8 \) ? \\ A & \( (x-8)(x+1) \) \\ B & \( (x-2)(x+4) \) \\ C & \( (x-4)(x+2) \) \\ D & \( (x+8)(x-1) \)\end{tabular}
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To factor the quadratic expression \( x^{2}+7x-8 \), we look for two numbers that multiply to give -8 (the constant term) and add up to 7 (the coefficient of the middle term). The numbers 8 and -1 fit this criteria since \( 8 \times -1 = -8 \) and \( 8 + (-1) = 7 \). So, we can factor the expression as \( (x + 8)(x - 1) \), which corresponds to option D! Now go ahead and verify it by expanding \( (x + 8)(x - 1) \) to check that it results back in \( x^{2} + 7x - 8 \). Happy factoring!