View Policies Current Attempt in Progress Find the \( z \)-score of the value 96 in a dataset with mean 73 and standard deviation 10 . Interpret the \( z \)-score in terms of number of standard deviations above or below the mean. Give your answers accurate to three decimal places. \( z \)-score \( = \) i This value of 96 is \( \mathbf{i} \)

To find the \( z \)-score of the value 96 in a dataset with a mean (\( \mu \)) of 73 and a standard deviation (\( \sigma \)) of 10, you can use the following formula: \[ z = \frac{X - \mu}{\sigma} \] Where: - \( X \) is the value in question (96), - \( \mu \) is the mean (73), - \( \sigma \) is the standard deviation (10). Plugging in the values: \[ z = \frac{96 - 73}{10} = \frac{23}{10} = 2.300 \] **Interpretation:** A \( z \)-score of **2.300** means that the value 96 is **2.300 standard deviations above** the mean of the dataset. --- **Final Answer:** \( z \)-score \( = \) **2.300** This value of 96 is **2.300 standard deviations above** the mean.