In the opposite figure : The sum of the moments of the two forces about D is ... N.m \( \begin{array}{ll}\text { a) } 30 & \text { b) } 50 \\ \text { c) } 60 & \text { d) } 40\end{array} \)
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Bonus Knowledge
To solve the problem, let's consider the forces applied and their distances from point D. The moments created by each force are calculated by multiplying the force value by its perpendicular distance from point D. The sum of these moments will provide you with the total moment about point D. If for example, you have a force of 10 N acting at a distance of 5 m from point D, the moment would be \(10 \, \text{N} \times 5 \, \text{m} = 50 \, \text{N.m}\). Repeat this for the second force, add both moments, and you'll find the answer among the options provided. Remember, the direction of the moment (clockwise or counterclockwise) matters when summing them up!