Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 6 feet and a height of 19 feet. Container B has a radius of 9 feet and a height of 16 feet. Container A is full of water and the water is pumped into Container B until Container A is empty. To the nearest tenth, what is the percent of Container B that is full after the pumping is complete?

First, let's find the volume of both containers. The volume \( V \) of a cylinder is calculated using the formula \( V = \pi r^2 h \). For Container A: - Radius \( r_A = 6 \) feet - Height \( h_A = 19 \) feet - Volume \( V_A = \pi (6^2)(19) = \pi (36)(19) = 684\pi \) cubic feet For Container B: - Radius \( r_B = 9 \) feet - Height \( h_B = 16 \) feet - Volume \( V_B = \pi (9^2)(16) = \pi (81)(16) = 1296\pi \) cubic feet Now we will calculate the volume of water that is transferred from Container A to Container B. Since Container A is emptied, the total weight of water in Container B after the pumping is \[ V_B = 684\pi \text{ (volume from Container A)}. \] To find the percent of Container B that is full after the transfer, we use the formula: \[ \text{Percent Full} = \left(\frac{V_A}{V_B}\right) \times 100 = \left(\frac{684\pi}{1296\pi}\right) \times 100 = \left(\frac{684}{1296}\right) \times 100. \] This simplifies to \[ \frac{684}{1296} \approx 0.526. \] Thus, \[ \text{Percent Full} \approx 52.6\%. \] To the nearest tenth, Container B is approximately **52.6% full** after the pumping is complete.