c) \( 125+25 \div 5-(250 \times 2 \div 50)+144 \div 12-15= \)
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To solve the expression \( 125 + 25 \div 5 - (250 \times 2 \div 50) + 144 \div 12 - 15 \), we follow the order of operations (PEMDAS/BODMAS: Parentheses/Brackets, Exponents/Orders, Multiplication and Division, Addition and Subtraction). 1. Calculate the divisions first: - \( 25 \div 5 = 5 \) - \( 250 \times 2 = 500 \); then \( 500 \div 50 = 10 \) - \( 144 \div 12 = 12 \) 2. Now substitute those values back into the expression: - \( 125 + 5 - 10 + 12 - 15 \) 3. Now perform addition and subtraction from left to right: - \( 125 + 5 = 130 \) - \( 130 - 10 = 120 \) - \( 120 + 12 = 132 \) - \( 132 - 15 = 117 \) Therefore, the final answer is \( 117 \).