Solve using substitution. \( \begin{array}{l}y=5 \\ -3 x-3 y=-18 \\ \text { Submit }\end{array} \)
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To solve the system using substitution, we start with the first equation \( y = 5 \). Now, we can substitute this value of \( y \) into the second equation. This leads us to: \(-3x - 3(5) = -18\) Simplifying this gives: \(-3x - 15 = -18\) Next, add 15 to both sides: \(-3x = -3\) Now, divide by -3 to isolate \( x \): \(x = 1\) Thus, the solution to the system is \( x = 1 \) and \( y = 5 \). You can check your answers by plugging them back into the original equations to ensure they hold true. Fun fact: Matrices and determinants can also be used to tackle such systems!