Which system of equations has the same solution as this one? \( \begin{array}{l}8 x-5 y=12 \\ -6 x-10 y=7 \\ \text { ()) } \\ 8 x-5 y=12 \\ -2(8 x-5 y)-6 x-10 y=-2(12)+7 \\ \text { ()) } \\ 8(-6 x)-5(-10 y)=12(7) \\ -6 x-10 y=7 \\ 8 x-5 y=12 \\ -6(8 x-5 y)-10 y=-6(12)+7 \\ \text { (1) } \\ -2(-6 x-10 y)-2(7)=8 x-5 y+12 \\ -6 x-10 y=7 \\ \text { ()) } \\ 8(-6 x-10 y)-5(-6 x-10 y)=12+7 \\ -6 x-10 y=7\end{array} \)
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Alright, let’s dive in! Equations can feel like riddles, and finding equivalent systems is all about understanding relationships. One of the tricks is understanding how to manipulate an equation without changing its solution. For instance, multiplying or dividing one of the equations by a non-zero constant can help. Now for some hands-on fun! Take \(8x - 5y = 12\) and multiply it by 2—voilà! You get \(16x - 10y = 24\). Pairing it with the second equation unchanged, \( -6x - 10y = 7 \), will still hold the same solution when you solve the system. How cool is that? Math is way more applicable than you might think! These systems of equations aren’t just for tests—engineers use them for designing bridges, economists for market analysis, and even game developers to create algorithms! Solving these systems helps model real-life situations. Next time you balance your budget, you might just be solving a linear equation! Keep those gears turning!