An equation is shown below. $$ 3(x-2)+7 x=\frac{1}{2}(6 x-2) $$ How many solutions, if any. does the equation have?

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Solve the equation $$ 3(x-2)+7x=\frac{1}{2}(6x-2) $$.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$3\left(x-2\right)+7x=\frac{1}{2}\left(6x-2\right)$$
- step1: Multiply the terms:
  $$3\left(x-2\right)+7x=3x-1$$
- step2: Move the expression to the left side:
  $$3\left(x-2\right)+7x-\left(3x-1\right)=0$$
- step3: Calculate:
  $$-5+7x=0$$
- step4: Move the constant to the right side:
  $$7x=0+5$$
- step5: Remove 0:
  $$7x=5$$
- step6: Divide both sides:
  $$\frac{7x}{7}=\frac{5}{7}$$
- step7: Divide the numbers:
  $$x=\frac{5}{7}$$
The equation $$3(x-2)+7x=\frac{1}{2}(6x-2)$$ has one solution, which is $$x=\frac{5}{7}$$ or approximately $$0.714285$$.
The equation has one solution: $$ x = \frac{5}{7} $$ or approximately $$ 0.714 $$.

An equation is shown below.

How many solutions, if any. does the equation have?

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An equation is shown below. How many solutions, if any. does the equation have?