A spinner has 20 equally sized sections, 4 of which are green and 16 of which are blue. The spinner is spun and, at the same time, a fair coin is tossed. What is the probability that the spinner lands on green and the coin toss is heads? Do not round your answer.

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To find the probability that the spinner lands on green and the coin toss is heads, we can use the multiplication rule of probability.

1. **Calculate the probability of the spinner landing on green:**
   - There are 4 green sections out of a total of 20 sections.
   $$
   P(\text{Green}) = \frac{4}{20} = \frac{1}{5}
   $$

2. **Calculate the probability of the coin landing on heads:**
   - A fair coin has 2 sides (heads and tails), so the probability of landing on heads is:
   $$
   P(\text{Heads}) = \frac{1}{2}
   $$

3. **Calculate the combined probability:**
   - Since the spinner and the coin toss are independent events, we multiply their probabilities:
   $$
   P(\text{Green and Heads}) = P(\text{Green}) \times P(\text{Heads}) = \frac{1}{5} \times \frac{1}{2} = \frac{1}{10}
   $$

Thus, the probability that the spinner lands on green and the coin toss is heads is $$\frac{1}{10}$$.
The probability is $$\frac{1}{10}$$.

A spinner has 20 equally sized sections, 4 of which are green and 16 of which are blue. The spinner is spun and, at the same time, a fair coin is tossed. What is the probability that the spinner lands on green and the coin toss is heads? Do not round your answer.

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