a) \( 2\left(\frac{3}{2}+0,5\right)+\frac{1}{2} \) b) \( 1000 \times 5 \times \frac{2}{5}+1 \times 0 \) c) \( \frac{5}{6}-0 \times \frac{6}{5} \) d) \( 6 \times 3 \times \frac{1}{90}+9+0 \)
Real Tutor Solution
Answer
Solution
Reviewed and approved by the UpStudy tutoring team
Extra Insights
Let's break it down: a) First, we calculate inside the parentheses: \( \frac{3}{2} + 0.5 = 1.5 + 0.5 = 2 \). Then, \( 2 \times 2 + \frac{1}{2} = 4 + 0.5 = 4.5 \). b) Here, \( 1000 \times 5 \times \frac{2}{5} \) simplifies to \( 1000 \times 2 = 2000 \). But since we have \( 1 \times 0 \), this part contributes nothing. Thus, the result is \( 2000 + 0 = 2000 \). c) \( \frac{5}{6} - 0 \times \frac{6}{5} = \frac{5}{6} - 0 = \frac{5}{6} \). d) This computes as follows: \( 6 \times 3 \times \frac{1}{90} = \frac{18}{90} = \frac{1}{5} \). Adding 9 and 0, we get \( \frac{1}{5} + 9 = 9.2 \). So the final results are: a) \( 4.5 \) b) \( 2000 \) c) \( \frac{5}{6} \) d) \( 9.2 \)