Question

Find the intersection point of the lines given by the equations \( y = 2x + 1 \) and \( y = -0.5x + 3 \).

Ask by Reeves Turner. in South Africa
Jan 23,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The lines intersect at the point \( (0.8, 2.6) \).

Solution

To find the intersection point of the two lines given by the equations: 1. \( y = 2x + 1 \) 2. \( y = -0.5x + 3 \) **Step 1: Set the equations equal to each other** Since both equations equal \( y \), we set them equal to find the \( x \)-coordinate of the intersection point. \[ 2x + 1 = -0.5x + 3 \] **Step 2: Solve for \( x \)** \[ 2x + 0.5x = 3 - 1 \\ 2.5x = 2 \\ x = \frac{2}{2.5} \\ x = 0.8 \] **Step 3: Substitute \( x = 0.8 \) into one of the original equations to find \( y \)** Using the first equation \( y = 2x + 1 \): \[ y = 2(0.8) + 1 \\ y = 1.6 + 1 \\ y = 2.6 \] **Conclusion:** The two lines intersect at the point \( (0.8,\ 2.6) \). **Alternatively, as fractions:** \[ x = \frac{4}{5}, \quad y = \frac{13}{5} \] So, the intersection point is \( \left( \frac{4}{5},\ \frac{13}{5} \right) \).

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To find the intersection point of the lines given by the equations \( y = 2x + 1 \) and \( y = -0.5x + 3 \), we need to set the two equations equal to each other: \[ 2x + 1 = -0.5x + 3 \] Now, let's solve for \( x \). First, we can add \( 0.5x \) to both sides: \[ 2x + 0.5x + 1 = 3 \] This simplifies to: \[ 2.5x + 1 = 3 \] Next, subtract 1 from both sides: \[ 2.5x = 3 - 1 \] \[ 2.5x = 2 \] Now, divide both sides by 2.5: \[ x = \frac{2}{2.5} = \frac{2 \times 10}{25} = \frac{20}{25} = \frac{4}{5} \] Now that we have \( x = \frac{4}{5} \), we can substitute this value back into either of the original equations to solve for \( y \). Let's use the first equation: \[ y = 2x + 1 \] Substituting \( x = \frac{4}{5} \): \[ y = 2\left(\frac{4}{5}\right) + 1 = \frac{8}{5} + \frac{5}{5} = \frac{13}{5} \] Thus, the intersection point of the lines is: \[ \left( \frac{4}{5}, \frac{13}{5} \right) \]

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