A mechanic has logged the following numbers of hours in maintaining and repairing a certain Detroit Series 6 diesel engine for ten different servicings. \( \begin{array}{llllllll}8.4 & 15.6 & 20.3 & 6.5 & 11.1 & 19.4 & 18.3 & 7.2\end{array} \quad 9.7 \) a. Find the mean for the hours logged. b. Find the median for the hours logged. c. If the mechanic earns \( \$ 17.95 \) per hour, how much does he earn doing the median servicing on this engine? a. The mean for the hours logged is (Type an integer or a decimal.)
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To find the mean, you add all the hours together and divide by the total number of entries. The total of the logged hours is: \( 8.4 + 15.6 + 20.3 + 6.5 + 11.1 + 19.4 + 18.3 + 7.2 + 9.7 = 116.1 \) hours. Dividing by the total number of servicings (10), the mean is \( \frac{116.1}{10} = 11.61 \). So, the mean for the hours logged is \( 11.61 \). For the median, you arrange the numbers in ascending order: \( 6.5, 7.2, 8.4, 9.7, 11.1, 15.6, 18.3, 19.4, 20.3 \). Since there’s an even number of observations, you take the average of the two middle numbers (9.7 and 11.1). So, the median is \( \frac{9.7 + 11.1}{2} = 10.4 \). To find out how much the mechanic earns doing the median servicing, you multiply the median hours (10.4) by the hourly rate ($17.95): \( 10.4 \times 17.95 \approx 186.38 \). Thus, the mechanic earns approximately \( \$186.38 \) during the median servicing.