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In a big cooler in the kitchen there are the following drinks: 8 cans of soda, 9 bottles of juice, and 2 cans of juice. But, there are no bottles of soda. Yoko just came in from playing outside and is going to choose one of these drinks at random from the cooler. What is the probability that the drink Yoko chooses is in a bottle or is a soda? Do not round intermediate computations, and round your answer to the nearest hundredth. (If necessary, consult a list of formulas.)

Ask by Gibson Donnelly. in the United States
Dec 08,2024

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The probability is approximately 0.89.

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To find the probability that the drink Yoko chooses is in a bottle or is a soda, we first identify the total number of drinks and then the favorable outcomes. Total drinks: - Cans of soda = 8 - Bottles of juice = 9 - Cans of juice = 2 Total drinks = 8 (soda) + 9 (juice) + 2 (juice) = 19 drinks. Next, we find the drinks that are in a bottle or are soda. Since there are no bottles of soda, we can simply count: - Bottles of juice = 9 - Cans of soda = 8 Favorable outcomes = 9 (bottles of juice) + 8 (cans of soda) = 17. Now, we calculate the probability: \[ \text{Probability} = \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{17}{19} \] Now we can divide: \[ \frac{17}{19} \approx 0.89473684211 \] Rounding to the nearest hundredth gives us: **Probability ≈ 0.89**.

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