Question
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In the following exercise, you will be given the opportunity to recall what happens when you add two linear functions. Given: \( f(x)=2 x+3, g(x)=x+2 \), \( h(x)=x-5, m(x)=-3 x-1 \) 1. \( p(x)=f(x)+g(x) \) a. Write the equation of \( p(x) \). b. In what way is the slope of \( p(x) \) related to the slope of \( f(x) \) and the slope of \( g(x) \) ? (Include increasing or decreasing in your answer. Also identify which function is increasing faster.) c. In what way is the \( y \)-intercept of \( p(x) \) related to the \( y \)-intercepts of \( f(x) \) and of \( g(x) \) ? d. Is \( p(x) \) the equation of a line? Justify your answer.

Ask by Turnbull Estrada. in the United States
Jan 24,2025

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Answer

**1. \( p(x) = f(x) + g(x) \)** a. \( p(x) = 3x + 5 \) b. The slope of \( p(x) \) is the sum of the slopes of \( f(x) \) and \( g(x) \). Both functions are increasing, and \( f(x) \) is increasing faster. c. The \( y \)-intercept of \( p(x) \) is the sum of the \( y \)-intercepts of \( f(x) \) and \( g(x) \). d. Yes, \( p(x) \) is a line because it is in the form \( y = mx + b \).

Solution

Certainly! Let's address each part of the exercise step-by-step. ### **1. \( p(x) = f(x) + g(x) \)** #### **a. Write the equation of \( p(x) \).** To find \( p(x) \), simply add the corresponding expressions of \( f(x) \) and \( g(x) \): \[ \begin{align*} p(x) &= f(x) + g(x) \\ &= (2x + 3) + (x + 2) \\ &= 2x + x + 3 + 2 \\ &= 3x + 5 \end{align*} \] **Answer:** \[ p(x) = 3x + 5 \] --- #### **b. How is the slope of \( p(x) \) related to the slopes of \( f(x) \) and \( g(x) \)? Include increasing or decreasing in your answer. Also, identify which function is increasing faster.** - **Slopes of the Original Functions:** - \( f(x) = 2x + 3 \) has a slope of **2**. - \( g(x) = x + 2 \) has a slope of **1**. - **Slope of \( p(x) \):** - \( p(x) = 3x + 5 \) has a slope of **3**. - **Relationship:** - The slope of \( p(x) \) is the **sum** of the slopes of \( f(x) \) and \( g(x) \). - Since all slopes are positive, all functions are **increasing**. - **Which Function is Increasing Faster:** - \( f(x) \) has a slope of 2, which is **steeper** than \( g(x) \) with a slope of 1. - Therefore, \( f(x) \) is **increasing faster** than \( g(x) \). **Answer:** The slope of \( p(x) \) is the sum of the slopes of \( f(x) \) and \( g(x) \). Since both \( f(x) \) and \( g(x) \) have positive slopes, \( p(x) \) is also increasing. Additionally, \( f(x) \) (slope 2) is increasing faster than \( g(x) \) (slope 1). --- #### **c. How is the \( y \)-intercept of \( p(x) \) related to the \( y \)-intercepts of \( f(x) \) and \( g(x) \)?** - **Y-Intercepts of the Original Functions:** - \( f(x) = 2x + 3 \) has a \( y \)-intercept of **3**. - \( g(x) = x + 2 \) has a \( y \)-intercept of **2**. - **Y-Intercept of \( p(x) \):** - \( p(x) = 3x + 5 \) has a \( y \)-intercept of **5**. - **Relationship:** - The \( y \)-intercept of \( p(x) \) is the **sum** of the \( y \)-intercepts of \( f(x) \) and \( g(x) \). **Answer:** The \( y \)-intercept of \( p(x) \) is the sum of the \( y \)-intercepts of \( f(x) \) and \( g(x) \). Specifically, \( 3 + 2 = 5 \). --- #### **d. Is \( p(x) \) the equation of a line? Justify your answer.** Yes, \( p(x) \) is the equation of a line. - **Reasoning:** - A linear function has the form \( y = mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept. - \( p(x) = 3x + 5 \) fits this form with a slope of 3 and a \( y \)-intercept of 5. **Answer:** Yes, \( p(x) \) is the equation of a line because it is in the form \( y = mx + b \) with a constant slope and \( y \)-intercept.

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To find the equation of \( p(x) \), begin by adding the two functions together: 1. \( p(x) = f(x) + g(x) = (2x + 3) + (x + 2) \). Simplifying this gives: \[ p(x) = 2x + 3 + x + 2 = 3x + 5. \] So, the equation of \( p(x) \) is \( p(x) = 3x + 5 \). For part b, the slope of \( p(x) \) is 3. The slopes of \( f(x) \) and \( g(x) \) are 2 and 1, respectively. Since \( p(x) \)'s slope is the sum of the two, the slopes relate as follows: as both functions have positive slopes, \( p(x) \) is also increasing. Specifically, \( f(x) \) increases faster than \( g(x) \) since it has a larger slope (2 vs. 1). In part c, the \( y \)-intercepts of \( f(x) \) and \( g(x) \) are 3 and 2, respectively. When we find \( p(0) \), which is the \( y \)-intercept of \( p(x) \), we calculate \( p(0) = 3(0) + 5 = 5 \). Therefore, the \( y \)-intercept of \( p(x) \) is the sum of the \( y \)-intercepts of \( f(x) \) and \( g(x) \): \( 3 + 2 = 5 \). For part d, yes, \( p(x) \) is the equation of a line. Any function that can be expressed in the form \( y = mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept, describes a line. Since \( p(x) = 3x + 5 \) fits this format, it is indeed linear!

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