Question
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6. \( \frac{3}{4}+\left(\frac{1}{4}-\frac{1}{6}\right) \)

Ask by Harris Nunez. in the United States
Jan 24,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The final answer is \(\frac{5}{6}\).

Solution

To solve the expression: \[ \frac{3}{4} + \left( \frac{1}{4} - \frac{1}{6} \right) \] **Step 1: Simplify the expression inside the parentheses** \[ \frac{1}{4} - \frac{1}{6} \] To subtract these fractions, find a common denominator. The least common denominator (LCD) of 4 and 6 is 12. \[ \frac{1}{4} = \frac{3}{12} \\ \frac{1}{6} = \frac{2}{12} \] Now subtract: \[ \frac{3}{12} - \frac{2}{12} = \frac{1}{12} \] **Step 2: Add the result to \(\frac{3}{4}\)** \[ \frac{3}{4} + \frac{1}{12} \] Again, find a common denominator. The LCD of 4 and 12 is 12. \[ \frac{3}{4} = \frac{9}{12} \\ \frac{1}{12} = \frac{1}{12} \] Now add: \[ \frac{9}{12} + \frac{1}{12} = \frac{10}{12} \] **Step 3: Simplify the final fraction** \[ \frac{10}{12} = \frac{5}{6} \] **Final Answer:** \(\boxed{\dfrac{5}{6}}\)

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Extra Insights

To tackle this expression, let's simplify it step by step! First, focus on the parentheses: \( \frac{1}{4} - \frac{1}{6} \). To subtract these fractions, you need a common denominator, which for 4 and 6 is 12. Rewriting the fractions: \[ \frac{1}{4} = \frac{3}{12}, \quad \frac{1}{6} = \frac{2}{12} \] Now, subtracting these gives: \[ \frac{3}{12} - \frac{2}{12} = \frac{1}{12} \] Next, substitute this back into the original expression: \[ \frac{3}{4} + \frac{1}{12} \] Again, we need a common denominator to add these fractions. The least common denominator between 4 and 12 is 12. Rewrite \( \frac{3}{4} \): \[ \frac{3}{4} = \frac{9}{12} \] Now, combine the fractions: \[ \frac{9}{12} + \frac{1}{12} = \frac{10}{12} = \frac{5}{6} \] So, the final answer is: \[ \frac{5}{6} \]

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