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Multiply. \[ (x+11)\left(x^{3}+4 x-7\right) \]

Ask by Christensen Bright. in the United States
Jan 21,2025

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Answer

Multiply the polynomials to get \( x^4 + 11x^3 + 4x^2 + 37x - 77 \).

Solution

To multiply the polynomials \((x + 11)\) and \((x^3 + 4x - 7)\), follow these steps: 1. **Distribute each term in the first polynomial to each term in the second polynomial:** \[ (x + 11)(x^3 + 4x - 7) = x \cdot (x^3) + x \cdot (4x) + x \cdot (-7) + 11 \cdot (x^3) + 11 \cdot (4x) + 11 \cdot (-7) \] 2. **Perform the multiplication for each term:** \[ = x^4 + 4x^2 - 7x + 11x^3 + 44x - 77 \] 3. **Combine like terms and arrange them in descending order of degree:** \[ = x^4 + 11x^3 + 4x^2 + ( -7x + 44x ) - 77 \] \[ = x^4 + 11x^3 + 4x^2 + 37x - 77 \] **Final Answer:** \[ x^4 + 11x^3 + 4x^2 + 37x - 77 \]

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Bonus Knowledge

To multiply the expressions \((x + 11)(x^3 + 4x - 7)\), we can distribute \(x\) and \(11\) to each term in the second expression. First, distribute \(x\): \[ x \cdot (x^3 + 4x - 7) = x^4 + 4x^2 - 7x \] Next, distribute \(11\): \[ 11 \cdot (x^3 + 4x - 7) = 11x^3 + 44x - 77 \] Now, combine all the terms from both distributions: \[ x^4 + 4x^2 - 7x + 11x^3 + 44x - 77 \] Rearranging and combining like terms gives: \[ x^4 + 11x^3 + 4x^2 + (44 - 7)x - 77 = x^4 + 11x^3 + 4x^2 + 37x - 77 \] Thus, the final result of the multiplication is: \[ \boxed{x^4 + 11x^3 + 4x^2 + 37x - 77} \]

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