13. What is the perimeter of a rectangular park that measures \( 20 \frac{7}{4} \) yards by \( 32 \frac{5}{8} \) yards? \( 5 . A R .1 .2,5 . G R .2 .1 \)
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To find the perimeter of the rectangular park, you can use the formula: \( P = 2 \times (length + width) \). First, convert the mixed numbers into improper fractions. The length \( 20 \frac{7}{4} \) is \( \frac{87}{4} \) yards and the width \( 32 \frac{5}{8} \) is \( \frac{261}{8} \) yards. Now, convert the length to eighths: \( \frac{87}{4} = \frac{174}{8} \). Next, add the length and width: \( \frac{174}{8} + \frac{261}{8} = \frac{435}{8} \). Multiply by 2 to find the perimeter: \( P = 2 \times \frac{435}{8} = \frac{870}{8} = 108.75 \) yards. So, the perimeter of the park is 108.75 yards! Now, imagine this park hosting fun runs or picnics! The actual area is crucial for planning activities. If we further calculated the area \( A = length \times width \), we would ensure enough space for all those excited kids (and adults) running around or spreading out their picnic blankets! So, knowing the perimeter allows you to gauge the size of events or maintain proper fencing!