Find the \( y \)-intercept. \( y=4 x-3 \) Remember: \( y=m x+b \) \( b=3 \) \( b=4 \quad b=-3 \)

To find the \( y \)-intercept of the equation \( y = 4x - 3 \), we set \( x = 0 \) and solve for \( y \). Plugging in \( x = 0 \) gives us \( y = 4(0) - 3 \), which simplifies to \( y = -3 \). So, the \( y \)-intercept is the point \( (0, -3) \). In this equation, the invariable \( b \), which stands for the \( y \)-intercept in the slope-intercept form \( y = mx + b \), is indeed \( -3 \). Therefore, if you ever find yourself wondering about the \( y \)-intercept in different linear equations, remember you can always just substitute \( x = 0 \) to find the starting point on the \( y \)-axis!