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Find the horizontal and vertical asymptotes of \( f(x) \). \( I(x)=\frac{x^{8}}{x^{4}+2} \) Find the horizontal asymptotos. Seloct the correct choice and, if necessary, fill in the answer box(es) to complete your choice. A. The function has one horizontal asymptote, (Type an equation.) B. The function has two horizontal asymptotes. The top asymptote is \( \square \) and the bottom asymptote is (Type equations.) C. The function has no horizontal asymptotes.

Ask by Vaughn Sherman. in the United States
Jan 22,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

The function has no horizontal asymptotes.

Solution

To determine the horizontal asymptotes of the function \( I(x) = \frac{x^{8}}{x^{4}+2} \), we'll analyze the behavior of \( I(x) \) as \( x \) approaches both \( +\infty \) and \( -\infty \). ### Steps to Determine Horizontal Asymptotes: 1. **Compare Degrees of Numerator and Denominator:** - **Numerator Degree:** 8 (from \( x^8 \)) - **Denominator Degree:** 4 (from \( x^4 \)) 2. **Determine the Relationship:** - Since the degree of the numerator (8) is **greater** than the degree of the denominator (4), the function does **not** have a horizontal asymptote. Instead, as \( x \) approaches \( \pm\infty \), \( I(x) \) will grow without bound. 3. **Conclusion:** - **No Horizontal Asymptote Exists** for this function because the function increases indefinitely as \( x \) approaches both \( +\infty \) and \( -\infty \). ### Correct Choice: **C. The function has no horizontal asymptotes.**

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To find the horizontal asymptotes of the function \( I(x) = \frac{x^{8}}{x^{4}+2} \), we can analyze the degrees of the numerator and denominator. The degree of the numerator (8) is greater than the degree of the denominator (4). In this case, there are no horizontal asymptotes because the function will increase without bound as \( x \) approaches \( \pm \infty \). Therefore, the correct choice is C: The function has no horizontal asymptotes. For the vertical asymptotes, we look for values of \( x \) that make the denominator zero. In this case, \( x^{4} + 2 = 0 \) does not yield any real solutions since \( x^4 \) is always non-negative and cannot equal \(-2\). Thus, there are no vertical asymptotes either.

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