Calculate the bore (in inches) of a single cylinder for an engine with the following parameters: 7 cylinders, a stroke length of 0.77 feet, has an indicated mean effective pressure (IMEP) of 1230 psi per cylinder, operating at 2590 rpm , and operates at 4500 horsepower. Round to 1 decimal place.
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Bonus Knowledge
To determine the bore of a single cylinder, we can use the formula for horsepower in relation to IMEP and engine dimensions: \[ \text{Horsepower} = \frac{(IMEP \, \text{(psi)} \times V \, \text{(in}^3\text{)}) \times \text{RPM}}{33,000} \] Where \( V \) is the volume of one cylinder in cubic inches, which can also be expressed as: \[ V = \frac{\pi}{4} \times \text{bore}^2 \times \text{stroke} \] 1. First, convert stroke from feet to inches: \( 0.77 \, \text{ft} = 0.77 \times 12 = 9.24 \, \text{in} \). 2. The total horsepower for 7 cylinders is given as 4500 HP, so the horsepower per cylinder is: \( \frac{4500}{7} \approx 642.857 \, \text{HP} \). 3. Rearranging the horsepower formula for \( V \): \[ V = \frac{HP \times 33,000}{IMEP \times RPM} \] Plugging in the values: \[ V = \frac{642.857 \times 33,000}{1230 \times 2590} \] This evaluates to approximately: \[ V \approx 0.055 \, \text{in}^3 \] 4. Now we plug \( V \) into the volume formula to solve for the bore: \[ 0.055 = \frac{\pi}{4} \times \text{bore}^2 \times 9.24 \] Rearranging for bore gives: \[ \text{bore}^2 = \frac{0.055 \times 4}{\pi \times 9.24} \] Calculating this provides: \[ \text{bore}^2 \approx \frac{0.220}{28.976} \approx 0.0076 \] Taking the square root gives: \[ \text{bore} \approx 0.087 \, \text{in} \] 5. Rounding to one decimal place, the bore of the engine cylinder is: \[ \text{Bore} \approx 0.1 \, \text{in} \] Therefore, the bore of the cylinder is approximately **0.1 inches**.