Question
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Calculate the bore (in inches) of a single cylinder for an engine with the following parameters: 7 cylinders, a stroke length of 0.77 feet, has an indicated mean effective pressure (IMEP) of 1230 psi per cylinder, operating at 2590 rpm , and operates at 4500 horsepower. Round to 1 decimal place.

Ask by Burns Rojas. in Canada
Dec 09,2024

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Tutor-Verified Answer

Answer

The bore of a single cylinder is approximately 3.6 inches.

Solution

To calculate the bore of a single cylinder in an engine, we can use the following formula that relates the engine's power output, IMEP, stroke length, and the number of cylinders: \[ \text{Power} = \frac{IMEP \times V_d \times N}{33,000} \] Where: - Power is in horsepower (hp) - IMEP is in psi - \( V_d \) is the displacement volume per cylinder in cubic inches - \( N \) is the number of power strokes per minute First, we need to calculate the displacement volume \( V_d \) for a single cylinder. The displacement volume can be calculated using the formula: \[ V_d = \frac{\pi}{4} \times D^2 \times L \] Where: - \( D \) is the bore (diameter) of the cylinder in inches - \( L \) is the stroke length in inches Next, we need to determine \( N \), the number of power strokes per minute. For a 4-stroke engine, \( N \) is half the engine speed in rpm, and for a 2-stroke engine, it is equal to the engine speed in rpm. Assuming this is a 4-stroke engine: \[ N = \frac{2590}{2} = 1295 \text{ power strokes per minute} \] Now, we can rearrange the power formula to solve for \( V_d \): \[ V_d = \frac{Power \times 33,000}{IMEP \times N} \] Substituting the known values: \[ V_d = \frac{4500 \times 33,000}{1230 \times 1295} \] Calculating \( V_d \): \[ V_d = \frac{148500000}{1597350} \approx 92.94 \text{ cubic inches} \] Now we can substitute \( V_d \) back into the displacement volume formula to find the bore \( D \): \[ 92.94 = \frac{\pi}{4} \times D^2 \times 9.24 \] Where \( L = 0.77 \text{ feet} = 0.77 \times 12 = 9.24 \text{ inches} \). Rearranging to solve for \( D^2 \): \[ D^2 = \frac{92.94 \times 4}{\pi \times 9.24} \] Calculating \( D^2 \): \[ D^2 = \frac{371.76}{29.052} \approx 12.8 \] Now, taking the square root to find \( D \): \[ D \approx \sqrt{12.8} \approx 3.58 \text{ inches} \] Rounding to one decimal place, the bore of a single cylinder is: \[ \boxed{3.6} \text{ inches} \]

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Bonus Knowledge

To determine the bore of a single cylinder, we can use the formula for horsepower in relation to IMEP and engine dimensions: \[ \text{Horsepower} = \frac{(IMEP \, \text{(psi)} \times V \, \text{(in}^3\text{)}) \times \text{RPM}}{33,000} \] Where \( V \) is the volume of one cylinder in cubic inches, which can also be expressed as: \[ V = \frac{\pi}{4} \times \text{bore}^2 \times \text{stroke} \] 1. First, convert stroke from feet to inches: \( 0.77 \, \text{ft} = 0.77 \times 12 = 9.24 \, \text{in} \). 2. The total horsepower for 7 cylinders is given as 4500 HP, so the horsepower per cylinder is: \( \frac{4500}{7} \approx 642.857 \, \text{HP} \). 3. Rearranging the horsepower formula for \( V \): \[ V = \frac{HP \times 33,000}{IMEP \times RPM} \] Plugging in the values: \[ V = \frac{642.857 \times 33,000}{1230 \times 2590} \] This evaluates to approximately: \[ V \approx 0.055 \, \text{in}^3 \] 4. Now we plug \( V \) into the volume formula to solve for the bore: \[ 0.055 = \frac{\pi}{4} \times \text{bore}^2 \times 9.24 \] Rearranging for bore gives: \[ \text{bore}^2 = \frac{0.055 \times 4}{\pi \times 9.24} \] Calculating this provides: \[ \text{bore}^2 \approx \frac{0.220}{28.976} \approx 0.0076 \] Taking the square root gives: \[ \text{bore} \approx 0.087 \, \text{in} \] 5. Rounding to one decimal place, the bore of the engine cylinder is: \[ \text{Bore} \approx 0.1 \, \text{in} \] Therefore, the bore of the cylinder is approximately **0.1 inches**.

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